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There are 10 points in a plane of which no three points are collinear and 4 points are concyclic. The number of different circles that can be drawn through at least three points of these points is

(a) 116
(b) 120
(c) 117
(d) none of these

User Durdenk
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Final answer:

A student asked about the number of different circles that can be drawn with 10 points where no 3 are collinear and 4 are concyclic. The calculation showed 21 different circles can be formed, which did not match any of the provided options, making the correct answer '(d) none of these'.

Step-by-step explanation:

The question revolves around the number of different circles that can be formed in a plane with 10 points of which no three points are collinear and 4 points are concyclic.

To find a circle, we need to choose at least 3 non-collinear points. Since 4 points are concyclic, they form a unique circle among themselves. For the remaining 6 points, we can form circles by selecting them in groups of 3.

To calculate the total number of circles: We can select 3 points from the 6 non-concyclic points in C(6,3) ways. This gives us:

C(6,3) = 6! / (3!(6-3)!) = 20

The unique circle from the concyclic points is 1. So, the total number of different circles is 20+1=21 circles. However, none of the provided options (a) 116, (b) 120, or (c) 117 matches the calculated number of circles. Therefore, the answer is (d) none of these.

User LihO
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