Final answer:
The distance between two points on a wave 60° out of phase can be found by first calculating the wavelength and then taking one-sixth of that length since 60° is one-sixth of a full wave cycle. The distance is 0.12 m for a wave with 500 Hz frequency and 360 m/s velocity.
Step-by-step explanation:
The question is asking for the distance between two points on a wave that are 60° out of phase. To find this, we must first find the wavelength of the wave using the formula λ = v / f where λ is the wavelength, v is the velocity, and f is the frequency of the wave. With a frequency of 500 Hz and a velocity of 360 m/s, the wavelength λ = 360 m/s / 500 Hz = 0.72 m. Since 360° corresponds to a full wavelength, 60° out of phase corresponds to 60°/360° = 1/6 of the wavelength. Therefore, the distance between two points 60° out of phase is 1/6 of 0.72 m, which is 0.12 m.