Final answer:
Calculating the days between 8th November 2006 and 8th January 2009, and then dividing by 7 to find the remainder, we find that the day of the week on 8th January 2009 was Thursday.
Step-by-step explanation:
To determine what day of the week it was on 8th January 2009, we can calculate the number of days that have passed since 8th November 2006 and apply that to the known weekday.
Step-by-Step Calculation
- Calculate the total days from 8th November 2006 to 8th November 2007. This is one year, which is 365 days since 2007 was not a leap year.
- Add the days from 8th November 2007 to 8th January 2008. November has 30 days, so 22 days in November plus 31 days in December makes it 53 days.
- Now add the days for the entire year of 2008. Since 2008 was a leap year, it had 366 days.
- Finally, add the days from 8th January 2008 to 8th January 2009. This is another year, but since 2009 is not a leap year, it has 365 days.
- Add up all the days: 365 + 53 + 366 + 365 = 1149 days.
- To find out the day of the week, divide the total days by 7 (the number of days in a week) to find the remainder. 1149 days ÷ 7 days/week = 164 weeks with a remainder of 1.
- Since the remainder is 1, and the original date, 8th November 2006, was a Wednesday, we add one day to Wednesday, resulting in Thursday.
Therefore, the day of the week on 8th January 2009 was Thursday.