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A diatomic ideal gas initially at 273 K is given 100 cal heat due to which system did 209 J work. Molar heat capacity (Cm) of gas for the process is:

A. 3/2 R
B. 5/2 R
C. 5/4 R
D. 5 R

User Riwen
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1 Answer

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The correct answer to this question is C. 5/4 R.

What is the Molar heat capacity (Cm) of gas for the process?

First, convert the heat absorbed from calories to Joules:

100 cal * 4.184 J/cal = 418.4 J

2. Apply the first law of thermodynamics:

For a closed system undergoing a change in temperature, the first law of thermodynamics states:

ΔU = Q + W

Where:

ΔU is the change in internal energy

Q is the heat absorbed

W is the work done by the system

For an ideal gas at constant pressure, the change in internal energy is related to the change in temperature by:

ΔU = nCvΔT

Where:

n is the number of moles of gas

Cv is the molar heat capacity at constant volume

ΔT is the change in temperature

Substitute the expressions for ΔU and Q in the first law equation:

nCvΔT = 418.4 J + 209 J

Rearrange for Cv:

Cv = (418.4 J + 209 J) / (nΔT)

5. Molar heat capacity at constant pressure (Cp):

For a diatomic ideal gas, the relationship between Cp and Cv is:

Cp = Cv + R

Where:

R is the gas constant

Substitute the expression for Cv from step 4:

Cp = [(418.4 J + 209 J) / (nΔT)] + R

Therefore, the molar heat capacity (Cp) of the gas for this process is a constant multiple of R. Since the work done (W) is positive, Cp will be greater than Cv. The only option that fits this observation is 5/4 R.

User Abasu
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