Final answer:
To prepare 1-chloropropane, Propanol-1 can be reacted with thionyl chloride (SOCl2) in the presence of pyridine; this method involves a nucleophilic substitution that leads specifically to 1-chloropropane. Therefore, the correct option is C.
Step-by-step explanation:
In order to prepare 1-chloropropane, there are several reactants that can be employed, and the correct option from the ones provided is C. Propanol-1 with thionyl chloride (SOCl2) in the presence of pyridine. This method involves the nucleophilic substitution of the hydroxyl group (-OH) in propanol-1 with a chlorine ion (Cl-), facilitated by thionyl chloride, to produce 1-chloropropane and byproducts, which are gaseous and can be easily removed.
The other options listed involve either a different type of mechanism or product formation: A involves a free radical addition mechanism leading to 2-chloropropane, and B would ultimately form 1,3-dichloropropane following an anti-Markovnikov addition and subsequent substitution which isn't specific to preparing 1-chloropropane. Therefore, only option C is the most straightforward and specific method for preparing 1-chloropropane.