123k views
5 votes
If a+b+c=0 and |a|=3; |b|=5; |c|=7, find the angle between a vector and b

A. 60°
B. 30°
C. 45°
D. none of these

1 Answer

3 votes

Final answer:

To find the angle between two vectors when a + b + c = 0 and |a| = 3, |b| = 5, and |c| = 7, we can use the dot product formula. Solving the equation -60 = 12(5) cos(θ), we find that cos(θ) = -1/2, which corresponds to angles of 120° or 240°. However, since none of the provided options match these angles, the correct answer is D. none of these.

Step-by-step explanation:

To find the angle between two vectors, we can use the dot product formula:

a · b = |a| |b| cos(θ)

Given that a + b + c = 0, we can rearrange it to a = -b - c. Substituting this into the dot product formula:

(-b - c) · b = |-b - c| |b| cos(θ)

Simplifying the dot product:

-(b · b) - (c · b) = |-b - c| |b| cos(θ)

Since |a| = 3, |b| = 5, and |c| = 7, the equation becomes:

-(5 · 5) - (7 · 5) = |-(-b - c)| |5| cos(θ)

Simplifying further:

-25 - 35 = |b + c| 5 cos(θ)

-60 = 12(5) cos(θ)

cos(θ) = -1/2

From the unit circle, we know that the angle whose cosine is -1/2 is 120° or 240°. However, since the options provided are 60°, 30°, 45°, and none of these, the correct answer is D. none of these.

User Faheem
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.