Final answer:
The given problem provides information about the number of students who like different combinations of the games Chess, Caroms, and Judo.
By assuming the number of students who like only Chess and Caroms, only Caroms and Judo, only Chess and Judo, and all three games is the same, we can calculate the possible number of students in the class. The correct answer is B. 40.
Step-by-step explanation:
The given problem provides information about the number of students who like different combinations of the games Chess, Caroms, and Judo. Let's assume that the number of students who like only Chess and Caroms is x. Similarly, the number of students who like only Caroms and Judo, only Chess and Judo, and all three games is also x. Now, let's calculate the possible number of students in the class:
- Students who like only Chess and Caroms: x
- Students who like only Caroms and Judo: x
- Students who like only Chess and Judo: x
- Students who like all three games: x
Since these four groups of students represent the total number of students in the class, the total number of students can be found by adding these values: 4x.
Given that x is an integer, we need to find a value of x that makes 4x a possible number of students. The options provided are A. 30, B. 40, C. 50, and D. 70. Among these options, a possible value of x is 10. Substituting x = 10, we find that the total number of students in the class is 4x = 40, which matches option B. Therefore, the correct answer is B. 40.