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A metal cube of edge 5 cm and density 9.0 g cm⁻³ is suspended by a thread so as to be completely immersed in a liquid of density 1.2 g cm⁻³. Find the tension in thread. (Take g = 10 m s⁻²)

User Binary
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Final answer:

The tension in the thread is 11250 N. The tension in the thread is equal to the weight of the metal cube, which can be calculated using the provided density and edge length. The buoyant force acting on the cube is equal to its weight, which is also equal to the tension in the thread.

Step-by-step explanation:

To find the tension in the thread, we need to determine the weight of the metal cube.

The weight of an object can be calculated using the formula weight = mass x gravity.

In this case, the mass of the cube is its volume multiplied by its density.

The volume of a cube is calculated by cubing its edge length.

So, the mass of the cube can be calculated as (5 cm)^3 x 9.0 g/cm³.

Once we have the mass, we can calculate the weight using the formula weight = mass x gravity.

The weight of the cube is equal to its tension, since it is suspended by the thread.

So, the tension in the thread is equal to the weight of the cube.

The density of the liquid is provided as 1.2 g/cm³.

Since the cube is completely immersed in the liquid, the buoyant force acting on it is equal to the weight of the liquid displaced by the cube.

The buoyant force can be calculated using the formula buoyant force = density of liquid x volume of submerged part of the cube x gravity.

Since the cube is completely submerged, the volume of the submerged part is equal to the volume of the cube.

So, the buoyant force is equal to the weight of the cube, which is equal to the tension in the thread.

Substituting the given values into the formulas, we have:

Mass of the cube = (5 cm)^3 x 9.0 g/cm³

= 1125 g

Weight of the cube = mass x gravity

= 1125 g x 10 m/s²

= 11250 N

Tension in the thread = Weight of the cube

= 11250 N

User Setrofim
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