Final answer:
The probability that one person picks a ticket with a higher number than another from two bags with tickets numbered 1 to 5 is 10 favorable outcomes over 25 total outcomes, or 2/5. Hence, the correct answer is 'D. none of these'.
Step-by-step explanation:
The question involves calculating the probability that one person picks a ticket with a number higher than another person from two bags, each containing tickets numbered 1 through 5. To determine this, we must consider all the possible combinations of ticket draws where the first person's ticket number is less than the second person's ticket number.
Let's denote the first person as A and the second person as B. The favorable outcomes for B to have a higher number than A are when A picks 1, B can have 2, 3, 4, or 5; when A picks 2, B can have 3, 4, or 5; and so on. This gives us the following pairs: (1,2), (1,3), (1,4), (1,5), (2,3), (2,4), (2,5), (3,4), (3,5), and (4,5), which results in 10 favorable outcomes.
Since both people are picking from the same set of numbers, the total number of outcomes is 5 (for A's pick) times 5 (for B's pick), which is 25. Thus, the probability that B picks a higher number than A is the number of favorable outcomes divided by the total number of outcomes, which equals 10/25 or 2/5. Therefore, the correct answer is neither of the options provided, and it's 'D. none of these'.