Final answer:
A uniform chain of length 2m is kept on a table such that a length of 60cm hangs freely from the edge of the table. The total mass of the chain is 4kg and the work done in pulling the entire chain on the table is 7.2 Joules.
Step-by-step explanation:
We can calculate the work done in pulling the entire chain on the table by considering the potential energy difference between the initial and final positions of the chain.
The potential energy of the hanging portion of the chain can be calculated as the product of its mass, length, and gravitational acceleration:
PE = (mass of hanging portion) x (length of hanging portion) x (gravitational acceleration)
Similarly, the potential energy of the entire chain on the table can be calculated as:
PE = (total mass of chain) x (length of table) x (gravitational acceleration)
The work done in pulling the entire chain on the table is the difference between these two potential energies:
Work done = Potential energy of the entire chain on the table - Potential energy of the hanging portion
Substituting the given values, we have:
Work done = (4 kg) x (2 m) x (9.8 m/s^2) - (0.6 kg) x (0.6 m) x (9.8 m/s^2)
Work done = 7.2 Joules