Final answer:
A closely wound solenoid 80 cm long has 5 layers of winding of 400 turns each. the diameter of the solenoid is 1.8 cm. if the current carried is 8.0 a, the magnitude of g inside the solenoid near its centre will be 2.51 x 10^-4 T.
Step-by-step explanation:
To find the magnitude of the magnetic field inside the solenoid near its center, we can use the formula:
B = μ₀nI, where B is the magnetic field, μ₀ is the permeability of free space (4π x 10^-7 Tm/A), n is the number of turns per unit length, and I is the current through the solenoid.
To calculate n, we divide the total number of turns by the length of the solenoid. In this case, there are 5 layers of winding with 400 turns each,
so the total number of turns is 5 x 400 = 2000.
The length of the solenoid is given as 80 cm,
so n = 2000 / 80
= 25 turns per centimeter
= 250 turns per meter.
Substituting the values into the formula,
we get B = (4π x 10^-7 Tm/A) x (250 turns/m) x (8.0 A)
= 8.0π x 10^-5 T
= 2.51 x 10^-4 T.
Therefore, the magnitude of the magnetic field inside the solenoid near its center is 2.51 x 10^-4 T.