Question

an iron ring 15 cm in diameter and 10 cm² in cross-section is svound with 200 turns of wire. for a flux density of i whim: and a relative permeability of 500, find the exciting current, the inductance and the stored energy.

Answer 1

The exciting current in the iron ring is 13.3 A. The inductance and stored energy cannot be calculated without knowing the length of the ring.

Step-by-step explanation:

To find the exciting current in the iron ring, we can use the formula:

exciting current = flux density x cross-sectional area x number of turns / (2 * relative permeability x diameter)

Plugging in the given values: flux density = 1 Wb/m², cross-sectional area = 10 cm² = 0.01 m², number of turns = 200, relative permeability = 500, and diameter = 15 cm = 0.15 m, we get:

exciting current = (1 Wb/m²) x (0.01 m²) x (200 turns) / (2 * 500 x 0.15 m) = 13.3 A

To find the inductance, we can use the formula:

inductance = (μ₀ x relative permeability x cross-sectional area x number of turns²) / length

Since the length of the ring is not given, we cannot calculate the inductance.

To find the stored energy, we can use the formula:

stored energy = (1/2) x inductance x current²

Since we don't have the inductance value, we cannot calculate the stored energy.