Question

50 ml of standard hard water containing 15 g of calcium carbonate per liter required 20 ml of edta solution for end point. calculate that 1 ml of above edta solution will be able to react with how much amount of calcium carbonate hardness?

Answer 1

1 ml of an EDTA solution can react with 0.0375 g of calcium carbonate hardness, determined through a titration where 50 ml of hard water with 15 g/L of CaCO3 required 20 ml of the EDTA solution to reach the endpoint.

Step-by-step explanation:

To calculate the amount of calcium carbonate hardness that 1 ml of EDTA solution can react with, we will use the given titration result. We know that 50 ml of the hard water required 20 ml of the EDTA solution to reach the endpoint.

Firstly, the amount of calcium carbonate (CaCO3) in 50 ml of the hard water can be calculated by:

• 15 g of CaCO3 in 1000 ml
• (15 g/L) × (50 ml/1000 ml) = 0.75 g of CaCO3

This 0.75 g of CaCO3 was completely titrated by 20 ml of the EDTA solution. Therefore, 1 ml of the EDTA solution will react with 0.75 g / 20 ml = 0.0375 g of CaCO3.

So, 1 ml of the EDTA solution can react with 0.0375 g of calcium carbonate hardness.