Question

A coil of area 0.04m² having 1000 turns is suspended perpendicular to a magnetic field of 5.0×10⁻⁵ Wbm⁻². It is rotated through 90∘ in 0.2 s. Calculate the average emf induced in it.

Answer 1

The average emf induced in the coil is 2π * 10^-3 V.

Step-by-step explanation:

The average emf induced in the coil can be calculated using the formula:

emf = B * A * ω * t * sin(θ)

Where emf is the induced electromotive force, B is the magnetic field strength, A is the area of the coil, ω is the angular velocity, t is the time taken to rotate the coil, and θ is the angle of rotation.

Substituting the given values into the formula:

emf = (5.0×10-5 Wbm-2) * (0.04m²) * (2π/0.2s) * 0.2s * sin(90∘)

Simplifying:

emf = (5.0×10-5 Wbm-2) * (0.04m²) * (2π/0.2s) * 0.2s * 1

emf = 2π * 10-3 V

Therefore, the average emf induced in the coil is 2π * 10-3 V.