Final answer:
The pressure at the center of the hollow sphere can be determined by considering the forces acting on the liquid. It is equal to the minimum pressure point plus the product of the density of the liquid, the acceleration due to gravity, and the radius of the sphere divided by the square root of 5.
Step-by-step explanation:
The pressure at the center of the hollow sphere can be determined by considering the forces acting on the ideal liquid inside the sphere. Since the sphere is moving horizontally with an acceleration of 2g, there is an apparent force acting on the liquid in the opposite direction. This apparent force is equal to the product of the density of the liquid, the acceleration due to gravity, and the radius of the sphere (p * g * R).
At the minimum pressure point, the pressure is equal to the atmospheric pressure plus the pressure due to the weight of the liquid. The weight of the liquid is equal to the product of the density, the acceleration due to gravity, and the height of the liquid (p * g * h).
Since the sphere is completely filled with liquid, the height of the liquid is equal to the radius of the sphere (h = R). Therefore, the pressure at the minimum pressure point is P0 + p * g * R.
Therefore, the pressure at the center of the sphere is P0 + p * g * R / √5.