Final answer:
A fair coin tossed 4 times creates a sample space with 16 outcomes. The subsets for more heads than tails are 5 outcomes, giving a probability of 5/16. For tails on even tosses, there are 4 outcomes, resulting in a probability of 1/4.
Step-by-step explanation:
When a fair coin is tossed 4 times, the sample space consists of 16 possible outcomes (24), since each toss has 2 possible outcomes (heads or tails). The sample space can be represented as follows:
- HHHH
- HHHT
- HHTH
- HHTT
- HTHH
- HTHT
- HTTH
- HTTT
- THHH
- THHT
- THTH
- THTT
- TTHH
- TTHT
- TTHH
- TTTT
For the event (a) where more heads than tails are obtained, the subsets are {HHHH, HHHT, HHTH, HTHH, THHH}. There are 5 outcomes in which there are more heads than tails out of the total 16 outcomes, so the probability of this event is P(a) = 5/16.
For the event (b) where tails occur on the even tosses, the subsets are {HTHT, HTTT, THTT, THHT}. There are 4 outcomes in which tails occur on even tosses out of the total 16 outcomes, so the probability of this event is P(b) = 4/16 or 1/4.