Final answer:
the magnitude of the force is 3.2 × 10^-14 N. The force experienced by the electron can be calculated using the equation F = qvBsinθ. In this case, the angle between the velocity and the magnetic field is 90 degrees or pi/2 radians.
Step-by-step explanation:
The force experienced by the electron can be calculated using the equation F = qvBsinθ, where F is the force, q is the charge of the electron, v is the velocity of the electron, B is the magnetic induction, and θ is the angle between the velocity and the magnetic field.
Since the electron is moving along the positive x-direction, the velocity vector is parallel to the x-axis.
This means that the angle between the velocity and the magnetic field, θ, is 90 degrees or pi/2 radians.
Plugging in the values given in the question, we have
F = (1.6×10^-19 C)(2×10^5 m/s)(1 T)sin(pi/2)
= (1.6×10^-19 C)(2×10^5 m/s)(1 T)(1)
= 3.2 × 10^-14 N.
Therefore, the magnitude of the force experienced by the electron is 3.2 × 10^-14 N.