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The pitch of a screw gauge is 1mm and there are 50 divisions on its cap. When nothing is put in between the studs , 44th division of circular scale coincides with reference line. When a glass plate is placed between the studs, the main scale reads three divisions and the circular scale reads 26 division.

a. The thickness of the plate is _____

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Final answer:

The thickness of the glass plate measured with a screw gauge having a pitch of 1mm and 50 divisions on the circular scale is 3.38mm, factoring in the zero error of the gauge.

Step-by-step explanation:

The student is asking how to determine the thickness of a glass plate using a screw gauge with specific parameters. The pitch of the screw gauge is given as 1mm, and it has 50 divisions on its circular scale. With no object between the studs, the 44th division aligns with the reference line. When the glass plate is measured, the main scale reads three divisions and the circular scale reads 26 divisions.

To calculate the thickness of the plate, we consider the reading when no object is placed, which is the zero error of the screw gauge. The zero error is given by: (50 - 44) / 50 × 1mm = 0.12mm.

Then, we use the main scale and circular scale readings with the plate in place.

The total thickness is given by the main scale reading plus the circular scale contribution minus the zero error: (3 × 1mm) + (26 / 50 × 1mm) - 0.12mm = 3.38mm.

Therefore, the thickness of the glass plate is 3.38mm.

User Sohaib Anwaar
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