Question

Write the equation of the line with a slope of 3/2 that contains the point (-4, -2). Select one: a. y=3/2x-2 b. y=3/2x-8 c. y=3/2x+4 d. y=3/2x-1

Answer 1

To find the equation of a line with a slope of 3/2 that passes through the point (-4, -2), we use the point-slope form and simplify it to y = 3/2x + 4.

Step-by-step explanation:

The equation of a line slope of 3/2 that contains the point (-4, -2) can be found using the point-slope form of a line, which is y - y1 = m(x - x1) where (x1, y1) is a point on the line and m is the slope.

Plugging in the given point and slope, we get:

y - (-2) = (3/2)(x - (-4))

Simplify this to:

y + 2 = (3/2)x + 6

To get to the y-intercept form (y = mx + b), subtract 2 from both sides:

y = (3/2)x + 6 - 2

y = (3/2)x + 4

So, the correct equation is y = 3/2x + 4.