Final answer:
In Physics, when a spring is cut in half and the same mass is suspended from it, the new period of oscillation is T/√2, given that the basic period of oscillation for a mass-spring system is proportional to the square root of the mass divided by the spring constant.
Step-by-step explanation:
The subject of this question is Physics, and it concerns the topic of simple harmonic motion and the properties of springs and pendulums. The question is focused on the impact of altering a spring's properties—specifically, cutting it in half—on the oscillation period T of a mass that is attached to it. In simple harmonic motion, the period of oscillation of a mass attached to a spring is given by the formula T = 2π√(m/k), where m is the mass and k is the spring constant. When a spring is cut into two equal halves, its spring constant doubles. The new period T' for one half of the spring is then T' = 2π√(m/(2k)) = T/√2. Therefore, the new period of oscillation when the spring is cut in half and the same mass is attached is T/√2.