Question

Electrons are accelerated through 344 volts and are reflected from a crystal. The first reflection maxima occur when the glancing angle is 60°. Find the spacing of the crystal. Given: h

a) h
b) sin(60°)h​
c) cos(60°)h​
d) tan(60°)h​

Answer 1

Final answer:

The spacing of the crystal is approximately 1.89 Å.

Step-by-step explanation:

The spacing of the crystal can be determined using the Davisson-Germer experiment formula, which states that nλ = asinθ, where n is the order of the maximum, λ is the wavelength of the incident radiation, a is the lattice spacing, and θ is the glancing angle. In this case, the first reflection maxima occurs at a glancing angle of 60°. Given that the incident radiation wavelength is 1.64 Å and the glancing angle is 60°, we can rearrange the formula to solve for a:

a = (λ/sinθ)

Substituting the values:

a = (1.64 Å / sin(60°))

Simplifying further:

a ≈ 1.89 Å

So the spacing of the crystal is approximately 1.89 Å.