Question

Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. Find the three integers:

a. 9, 11, 13
b. 11, 13, 15
c. 13, 15, 17
d. 7, 9, 11

Answer 1

To find the three consecutive odd integers, let's represent the first integer as x. The second integer would be x + 2, and the third integer would be x + 4. Solving the equation (x + 2) + (x + 4) = x + 13, we find that the three integers are 7, 9, and 11.

Step-by-step explanation:

To find the three consecutive odd integers, let's represent the first integer as x.

Since they are consecutive odd integers, the second integer would be x + 2, and the third integer would be x + 4.

According to the problem statement, the sum of the last two integers is 13 more than the first integer.

This can be translated into the equation (x + 2) + (x + 4) = x + 13.

Simplifying the equation, we have 2x + 6 = x + 13. Solving for x, we find that x = 7.

Therefore, the three integers are 7, 9, and 11.