Question

A 30-second commercial during Super Bowl XLIII in 2009 cost advertisers 3 million. For the first Super Bowl in 1967, an advertiser could have purchased approximately 26.19 minutes of advertising time for the same amount of money.

(a) Assuming that advertising cost is proportional to its length of time, find the cost of advertising, in dollars/second, during the 2009 Super Bowl.
cost = _____ dollars/second. (round to nearest cent and do not enter commas)

Answer 1

In 2009, a 30-second commercial during Super Bowl XLIII cost $100,000 per second. In 1967, an advertiser could have purchased approximately 26.19 minutes of advertising time for the same amount of money, costing around $1910.03 per second.

Step-by-step explanation:

To find the cost of the commercial per second, we need to divide the total cost of the commercial by the length of the commercial in seconds. In 2009, a 30-second commercial during Super Bowl XLIII cost $3 million. Therefore, the cost of the commercial per second would be $3 million divided by 30 seconds, which equals $100,000 per second.

In 1967, an advertiser could have purchased approximately 26.19 minutes of advertising time for the same amount of money. To find the cost of the commercial per second, we need to divide the total cost of the commercial by the length of the commercial in seconds. There are 60 seconds in every minute, so 26.19 minutes is equivalent to 26.19 times 60 seconds, which equals 1571.4 seconds. Therefore, the cost of the commercial per second would be $3 million divided by 1571.4 seconds, which approximates to $1910.03 per second.