Question

Al2Br3
Lewis structure

Answer 1

The Lewis structure of
`Al_2Br_3`involves two aluminum atoms surrounded by three bromine atoms, connected by single bonds. The arrangement satisfies the octet rule for bromine and achieves stability.

The Lewis structure of
`Al_2Br_3` involves depicting the arrangement of atoms and valence electrons in a molecule or ion. Aluminum bromide (
`Al_2Br_3`) consists of two aluminum atoms (Al) and three bromine atoms (Br). Aluminum has three valence electrons, while bromine has seven.

Starting with aluminum, place one Al atom at the center and surround it with three Br atoms. Connect the atoms with single bonds (represented by lines) to fulfill the octet rule for bromine, providing each Br atom with a full outer shell of electrons. Since aluminum tends to lose electrons, it contributes three electrons, forming three single bonds with the bromine atoms.

The Lewis structure can be illustrated as follows:

`\[ \text{Al} \quad \text{Br} \]`

`\[ | \, | \]`

`\[ \text{Br} \quad \text{Al} \quad \text{Br} \]`

Each line connecting the atoms represents a shared pair of electrons. As a result, the bromine atoms each satisfy the octet rule, and the aluminum atoms contribute their valence electrons to form a stable structure.