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I NEED HELP WITH THIS MATHHH

I NEED HELP WITH THIS MATHHH-example-1
User Ishpeck
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The solutions to the original equation are x= π/3, 5π/3 in radians.

To solve the equation 2 sin(x) - √3=0 in the interval [0,2π] we can follow these steps:

add √3 to both sides

2 sin(x) = √3

divided both sides by 2 sin(x) = √3/2

Identify the angles where sin(x)= √3/2 in the given interval

the solutions for sin(x)= √3/2 in the interval [0,2π] are x= π/3 and x= 5π/3.

Therefore, the solutions to the original equation are x= π/3, 5π/3 in radians.

User Shadocko
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