The solutions to the original equation are x= π/3, 5π/3 in radians.
To solve the equation 2 sin(x) - √3=0 in the interval [0,2π] we can follow these steps:
add √3 to both sides
2 sin(x) = √3
divided both sides by 2 sin(x) = √3/2
Identify the angles where sin(x)= √3/2 in the given interval
the solutions for sin(x)= √3/2 in the interval [0,2π] are x= π/3 and x= 5π/3.
Therefore, the solutions to the original equation are x= π/3, 5π/3 in radians.