Question

What is the temperature (in Kelvin) of 3.00 mol of nitrogen gas that occupies 32.0 L at 1.17 atm of pressure?

• Round your answer to the nearest whole number.
Provide your answer below:
K

Answer 1

a. √1

b. √2

c. √3

d.√4

e.√5

f.√6

Answer 2

Input variables, solve and simplify Identify knowns\(P=1.17~\mathrm{atm}\\ V=32~\mathrm{L}\\ n=3~\mathrm{mol}\)Convert units\(P=1.17~\mathrm{atm}\cdot \frac{101.325~\mathrm{kPa}}{1~\mathrm{atm}}\quad P=118.5502~\mathrm{kPa}\)Plug-in values\(118.5502~\mathrm{kPa}\cdot 32~\mathrm{L}=3~\mathrm{mol}\cdot 8.314~\mathrm{L}\cdot \mathrm{kPa}/(\mathrm{mol}\cdot \mathrm{K})\cdot T\) Multiply the numbers \(\bm{3793.6064~}\mathrm{L}\bm{\cdot }\mathrm{kPa}=3~\mathrm{mol}\cdot 8.314~\mathrm{L}\cdot \mathrm{kPa}/(\mathrm{mol}\cdot \mathrm{K})\cdot T\) Multiply the numbers \(3793.6064~\mathrm{L}\cdot \mathrm{kPa}=\bm{24.942~}\mathrm{L}\bm{\cdot }\mathrm{kPa}\bm{/}\mathrm{K}\cdot T\) Divide both sides by the same factor \(\frac{3793.6064~\mathrm{L}\cdot \mathrm{kPa}}{\bm{24.942~}\mathrm{L}\bm{\cdot }\mathrm{kPa}\bm{/}\mathrm{K}}=\frac{24.942~\mathrm{L}\cdot \mathrm{kPa}/\mathrm{K}\cdot T}{\bm{24.942~}\mathrm{L}\bm{\cdot }\mathrm{kPa}\bm{/}\mathrm{K}}\) Simplify \(T=152.09712132146580065753~\mathrm{K}\)