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Solve
121^5^x-11^1^2^x^+^2 for x

x=-2
x=-1
x=2
x=1

Solve121^5^x-11^1^2^x^+^2 for x x=-2 x=-1 x=2 x=1-example-1
User Katayoun
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1 Answer

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The solution to the equation
121^(5x)=11^(12x+2), is x=-1, found by expressing 121 as a power of 11, equating the exponents, and solving the resulting linear equation.

To solve the equation
121^(5x)=11^(12x+2), we can use the property of exponents which says that if
a^(n)=a^(m), then n=m, given that a is greater than 0 and not equal to 1.

First, we express 121 as a power of 11, since 121 is the same as
11^2.

Our equation thus becomes
(11^2)^(5x)=11^(12x+2).

Applying the rule of exponents that
(a^m)^n = a^(mn), we get
11^(10x)=11^(12x+2).

Now we can equate the exponents, which gives us 10x=12x+2.

Solving for x, we subtract 12x from both sides and get -2x=2.

Dividing both sides by -2, we find that x=-1.

User Yordanka
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