Final answer:
The pump pressure required to elevate a 9-lbmgal fluid 1000 ft is determined by using the hydrostatic pressure equation and considering the density of the fluid and the acceleration due to gravity.
Step-by-step explanation:
The correct answer to the question of computing the pump pressure required to pump a 9-lbmgal fluid from sea level to an elevation of 1000 ft with inertial and viscous frictional pressure changes being negligible revolves around principles found in fluid mechanics, a sub-discipline of physics.
To solve this, we need to apply the concept of hydrostatic pressure, which is the pressure due to the weight of a fluid over a given area. This pressure increases with depth and is given by the equation P = ρgh, where ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column. For a fluid with a density equivalent to water (ρ = 62.4 lbm/ft³), and elevating it to 1000 ft, we can calculate the required pump pressure.
First, convert 9 lbm/gal to the unit ρ lbm/ft³ using the conversion 1 gal = 0.13368 ft³. Then, determine g = 32.2 ft/s² (standard gravity). Using these values, we can substitute into the hydrostatic pressure equation to find the required pump pressure.