Question

a gas mixture contains 0.150 mol of oxygen (O₂) gas and 0.211 mol of argon (ar) gas. what is the mole fraction of O₂ in the mixture? report your answer with the correct number of significant figures.

Answer 1

The mole fraction of O₂ in a gas mixture containing 0.150 mol of O₂ and 0.211 mol of Ar is calculated as 0.416, using the mole fraction formula and maintaining the correct number of significant figures.

Step-by-step explanation:

To calculate the mole fraction of O₂ in the gas mixture, you should add the moles of both gases to get the total number of moles.

The formula for mole fraction (X) is X₂ = n₂ / (n₁ + n₂), where n₂ is the moles of O₂ and n₁ is the moles of Argon (Ar).

Thus, the mole fraction of O₂ is:

X₂ = n₂ / (n₁ + n₂) = 0.150 mol / (0.150 mol + 0.211 mol)

= 0.150 mol / 0.361 mol

≈ 0.4155

Therefore, the mole fraction of O₂ in the mixture, to the correct number of significant figures, is 0.416.