Final answer:
The resulting concentration of the C₆H₁₂O₆ solution after evaporating 85.9 mL of water from an initial 179.0 mL of a 0.539 M solution is approximately 1.037 M.
Step-by-step explanation:
To find the resulting concentration of a C₆H₁₂O₆ solution after water has been evaporated, you can use the concept of conservation of mass. The moles of solute before and after evaporation remain the same because evaporation does not affect the solute. You are provided with the initial volume and concentration, and the volume of water evaporated.
The initial moles of solute can be calculated by multiplying the initial concentration by the initial volume. Then, using the final volume (initial volume - volume evaporated), you can calculate the new concentration by dividing the initial moles of solute by the final volume.
Initial moles of C₆H₁₂O₆ = 0.539 M × 0.179 L = 0.0965 moles.
Final volume of solution = 179 mL - 85.9 mL = 93.1 mL = 0.0931 L.
The final concentration can be found by dividing the moles of C₆H₁₂O₆ by the final volume of the solution:
New concentration = 0.0965 moles / 0.0931 L ≈ 1.037 M.