Question

What volume of 0.35 M Ca(NO3)2 is

required to completely react with 50.0 mL
of 0.75 M K2SO4?
Ca(NO3)2 + K₂SO4 → CaSO4 + 2KNO3
[?] mL Ca(NO3)2

Answer 1

Answer: 107 ml

Step-by-step explanation:

Answer 2

Answer: 107 mL

Step-by-step explanation:

This equation can be modeled as MV=MV. Where M is molarity and V is volume.

The ratio between the two values is 1 mol to 1 mol so we do not have to deal will manipulating mol amounts and can just plug in values.

(0.35)V=(0.75)(50)

V=107 mL