Question

the partial molar volumes of acetone (propanone) and chloroform (trichloromethane) in a mixture in which the mole fraction of CHCl₃ is 0.4693 are 74.166 cm³ /mol and 80.235 cm³ /mol, respectively. what is the volume of a solution of mass 1.000 kg

Answer 1

To calculate the volume of the solution, we need to know the density of CHCl₃. By using the mole fraction of CHCl₃ and the given partial molar volumes of acetone and chloroform, we can derive the mass fraction of CHCl₃ in the solution. From there, we can calculate the mass and volume of CHCl₃ in the solution. The volume of the solution is the sum of the volumes of CHCl₃ and acetone.

Step-by-step explanation:

The volume of a solution can be calculated using the given information:

Mass of solution = 1.000 kg

Mole fraction of CHCl₃ = 0.4693

Partial molar volume of acetone (propanone) = 74.166 cm³/mol

Partial molar volume of chloroform (trichloromethane) = 80.235 cm³/mol

To calculate the volume of the solution, we can use the formula:

Volume = Mass of solution / Density

Since the density is not given, we can use the fact that the mole fraction of CHCl₃ is equal to the mass fraction of CHCl₃.

So, the mass fraction of CHCl₃ is 0.4693.

Now, we can calculate the mass of CHCl₃ in the solution:

Mass of CHCl₃ = Mass of solution × Mass fraction of CHCl₃

Next, we can calculate the volume of CHCl₃ in the solution:

Volume of CHCl₃ = Mass of CHCl₃ / Density of CHCl₃

Finally, the volume of the solution is the sum of the volumes of acetone and chloroform:

Volume of solution = Volume of CHCl₃ + Volume of acetone