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Let v(t) represent the speed of a car, where t is measured in seconds. What does the area under the curve and above the t-axis on the interval [0,10] represent?

A. Total distance traveled by the car in the first ten seconds
B. Acceleration of the car
C. Velocity of the car

1 Answer

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Final answer:

Correct option: A. Total distance traveled by the car in the first ten seconds.

The area under the curve of a velocity vs. time graph from t=0 to t=10 seconds represents the car's total displacement during that time interval, not the acceleration or the velocity at any given moment.

Step-by-step explanation:

The area under the curve of a velocity vs. time graph represents the displacement of an object. In the context of the car's motion, if v(t) is the car's speed and t is time in seconds, then the area under the curve of v(t) from t=0 to t=10 seconds gives the total displacement of the car during the first ten seconds. It indicates how far the car has traveled from its starting position. This area does not indicate the car's acceleration directly since acceleration is given by the slope of the velocity-time graph, not the area under it. Furthermore, the actual velocity of the car is the value of the function v(t) at any specific time, which is represented by a point on the curve rather than the area.

In a situation where the velocity is constant, the shape of the area under the curve would be rectangular, and thus, simple multiplication of velocity and time would give the displacement. When velocity varies, the area can be found using more complex geometric or calculus methods such as integrating the velocity function over the given time interval.

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