When 8 moles of SO2 are produced, the balanced chemical equation indicates that 4 moles of FeO will also be produced in accordance with the stoichiometric ratio in the reaction.
To determine the number of moles of FeO produced, we need to establish the stoichiometric relationship between the reactant (SO2) and the product (FeO) using the balanced chemical equation:
![\[2CuFeS_2 + 5O_2 \rightarrow 2Cu + 2FeO + 4SO_2.\]](https://img.qammunity.org/2024/formulas/chemistry/college/do7adv6xleogir9pp4rh1wypj7htkx6w8p.png)
From the balanced equation, we can observe that for every 4 moles of SO2 produced, 2 moles of FeO are formed. This ratio is derived from the coefficients of the balanced equation.
Therefore, to find the moles of FeO produced when 8 moles of SO2 are formed, we can set up a proportion:
![\[\frac{4 \text{ moles of SO}_2}{2 \text{ moles of FeO}} = \frac{8 \text{ moles of SO}_2}{x},\]](https://img.qammunity.org/2024/formulas/chemistry/college/hy2a9o7w9g1ld6jmaexvsauwd0bwictm0m.png)
where
represents the moles of FeO produced.
Solving for
:
![\[x = \frac{8 \text{ moles of SO}_2 * 2 \text{ moles of FeO}}{4 \text{ moles of SO}_2} = 4 \text{ moles of FeO}.\]](https://img.qammunity.org/2024/formulas/chemistry/college/481h40mud824ii11ftjfwrf2o5tgfz2y7o.png)