Final answer:
The momentum of the system before the collision is <30000, -34500, 0> kg m/s, for content loaded two cars that are headed towards an intersection and are due to collide anytime now. Car A has a mass of 1500 kg and a velocity of <20, 0, 0> m/s. Car B has a mass of 1500 kg and a velocity of <0, -23, 0>
Step-by-step explanation:
In order to find the momentum of a system, we need to calculate the momentum of each individual object and then add them together.
Momentum is calculated by multiplying the mass of an object by its velocity.
For car A, the mass is 1500 kg and the velocity is <20, 0, 0> m/s.
The momentum of car A is therefore 1500 kg × <20, 0, 0> m/s = <30000, 0, 0> kg m/s.
For car B, the mass is also 1500 kg and the velocity is <0, -23, 0> m/s.
The momentum of car B is 1500 kg × <0, -23, 0> m/s = <0, -34500, 0> kg m/s.
To find the momentum of the system, we add the momentum vectors of car A and car B together:
<30000, 0, 0> kg m/s + <0, -34500, 0> kg m/s = <30000, -34500, 0> kg m/s
Therefore, the momentum of the system before the collision is <30000, -34500, 0> kg m/s.