Question

In MATLAB, you can use your For Loop Condition variables within your execution code.

x = [2, 3, 4, 6];
for k = 2:4
x(k) = x(k-1) + 3*k;
end;

In the above code, k is the condition variable, and x is an array with existing elements. The execution statement uses k as the array index (which position in the array). What are the values of x after the code is executed?

A. x=[4,16,9,36]
B. x=[2,3,4,6]
C. x=[2,8,17,29]
D. x=[2,3,4]

Answer 1

The x array is updated using a formula based on the previous element and the current value of k in each iteration of the for loop.

Step-by-step explanation:

The correct answer is option C. x=[2,8,17,29]. In the given code, the For Loop starts with k = 2 and goes up to k = 4. In each iteration, the value of x(k) is updated based on the previous element in the array and the current value of k. The formula x(k) = x(k-1) + 3*k is used to calculate the new value.

Let's go through each iteration:

1. k = 2:
   x(2) = x(1) + 3*2 = 2 + 3*2 = 2 + 6 = 8
2. k = 3:
   x(3) = x(2) + 3*3 = 8 + 3*3 = 8 + 9 = 17
3. k = 4:
   x(4) = x(3) + 3*4 = 17 + 3*4 = 17 + 12 = 29

So, the final values of x after the code is executed are x = [2, 8, 17, 29].