Question

Wine is produced by the fermentation of grapes. in fermentation, the carbohydrate glucose (C₆H₁₂O₆) is converted to ethanol (C₂H₆O) and carbon dioxide (CO₂), according to the given balanced equation.

C₆H₁₂O₆(aq) -> 2C₂H₆O(aq) + 2CO₂(g)

how many grams of carbon dioxide (CO₂) are formed from of glucose ?

Answer 1

To determine the mass of CO2 produced from 200.0 g of glucose during fermentation, use stoichiometry with molar masses and the balanced chemical equation. This calculation results in 97.7 grams of CO2.

Step-by-step explanation:

During the fermentation of glucose, ethanol and carbon dioxide are produced as described by the balanced chemical equation: C6H12O6 (aq) → 2 C2H5OH(aq) + 2 CO2 (aq). To determine how many grams of CO2 are formed from the fermentation of glucose, we apply stoichiometry.

First, calculate the molar mass of glucose, which is 180.156 g/mol (6 carbon x 12.01 g/mol + 12 hydrogen x 1.008 g/mol + 6 oxygen x 16.00 g/mol) and the molar mass of CO2, which is 44.01 g/mol (1 carbon x 12.01 g/mol + 2 oxygen x 16.00 g/mol). Since the balanced equation shows that 1 mole of glucose produces 2 moles of CO2, we can use this ratio to find the mass of CO2 produced from 200.0 g of glucose.

Next, divide the mass of glucose by its molar mass to get the number of moles (200.0 g / 180.156 g/mol = 1.11 moles of glucose). Multiply the moles of glucose by the stoichiometric ratio (1.11 moles X 2 moles CO2 / 1 mole glucose = 2.22 moles of CO2) and then multiply by the molar mass of CO2 to get the mass (2.22 moles * 44.01 g/mol = 97.7 g of CO2).