Final answer:
The deuterium-tritium fusion reaction releases energy equivalent to 1.69 × 10⁹ kilojoules per mole of helium formed, for a proton-proton chain reaction is just one of many possible nuclear fusion reactions. Another one is deuterium-tritium fusion.
Step-by-step explanation:
The mass difference between the reactants and the products in the deuterium-tritium fusion reaction is 0.0188 amu. This mass difference corresponds to a release of 1.69 × 10⁹ kilojoules per mole of helium formed.
To calculate the energy produced in this specific reaction, we need to convert the given masses into moles and then use the molar mass to find the energy released.
First, let's convert the given masses of deuterium, tritium, and helium into moles.
Using the molar mass of deuterium (²H), which is 2.014 amu, we find that the mass of deuterium is approximately 1.659 x 10⁻²⁷ kg.
Dividing this mass by the molar mass, we get approximately 0.822 moles of deuterium.
By using the same process, we find that the mass of tritium is approximately 2.493 x 10⁻²⁷ kg, which is approximately 1.20 moles of tritium.
The mass of helium is approximately 4.0026 x 10⁻²⁷ kg, which is approximately 0.999 moles of helium.
Now, we can calculate the energy released by the reaction.
The energy released per mole of helium formed is 1.69 × 10⁹ kilojoules.
To find the energy released in this specific reaction, we multiply the energy released per mole by the number of moles of helium formed.
Thus, the energy produced in the deuterium-tritium fusion reaction is approximately 1.69 × 10⁹ kilojoules per mole of helium.