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calculate the osmotic pressure of 20 g/l glucose water solution against pure water through a semipermeable membrane at 298.15 k temperature. the semipermeable membrane is not permeable to glucose molecules and is permeable to water molecules. glucose molecular weight is 180.156 g/mol. report the result in [bar].

User Campbell
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Final answer:

The osmotic pressure can be calculated using the formula π = iMRT, where i is the van't Hoff factor, M is the molarity of the solution, R is the ideal gas constant, and T is the temperature. Substituting the given values, the osmotic pressure is calculated to be 2.9 bar.

Step-by-step explanation:

The osmotic pressure of a solution can be calculated using the formula:

π = iMRT

Where:

  • π is the osmotic pressure in bar
  • i is the van't Hoff factor, which is the number of particles a solute dissociates into (in this case, glucose does not dissociate in water so i = 1)
  • M is the molarity of the solution in mol/L (M = 20 g/L / 180.156 g/mol = 0.1107 mol/L)
  • R is the ideal gas constant, which is 0.0831 L·bar/mol·K
  • T is the temperature in Kelvin (T = 298.15 K)

Substituting the values into the formula:

π = (1)(0.1107 mol/L)(0.0831 L·bar/mol·K)(298.15 K)

π = 2.9 bar

User Takteek
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