The probability that the elapsed time between the tenth and eleventh arrival exceeds two days is approximately 13.53%.
In a Poisson process with a rate of λ arrivals per day, the time between arrivals follows an exponential distribution with parameter λ. Therefore, the probability of waiting more than t days for the next arrival is given by

In your specific case:
We want the probability of exceeding 2 days (t = 2) between the 10th and 11th arrival.
λ = 1 arrival per day.
Therefore, the probability P of exceeding 2 days is:

P = 0.1353
So, the probability that the elapsed time between the tenth and eleventh arrival exceeds two days is approximately 13.53%.