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Juan needs $7945 for a future project. He can invest $5000 now at an annual rate of 8.6%, compounded semiannually. Assuming that no withdrawals are made, how long will it take for him to have enough money for his project?

Do not round any intermediate computations, and round your answer to the nearest hundredth.

1 Answer

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Final answer:

Using the compound interest formula, Juan will need approximately 7.95 years for his $5000 investment at an annual rate of 8.6%, compounded semiannually, to grow to $7945.

Step-by-step explanation:

Juan needs $7945 for a future project. He can invest $5000 now at an annual rate of 8.6%, compounded semiannually. We will use the compound interest formula to determine how long it will take for his investment to grow to this amount. The formula for compound interest is:

A = P(1 + r/n)(nt)

where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money).
r = the annual interest rate (decimal).
n = the number of times that interest is compounded per year.
t = the time the money is invested for, in years.

In Juan's case:

  • P = $5000
  • r = 8.6% or 0.086
  • n = 2 (since interest is compounded semiannually)
  • A = $7945

We will solve for t:

$7945 = $5000(1 + 0.086/2)(2t)

Now, divide both sides by $5000:

1.589 = (1 + 0.043)(2t)

Then, take the natural logarithm of both sides to solve for t:

ln(1.589) = ln((1.043)(2t))

= 2t · ln(1.043)

After calculating the left and right side:

t = ln(1.589) / (2 · ln(1.043))

After performing the calculations, we will round the answer to the nearest hundredth:

t ≈ 7.95 years

It will take approximately 7.95 years for Juan's investment to grow to $7945.

User Kinjal Gohil
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