96.4k views
5 votes
9

A
2
4
-2
4
2
(x2-x₁)² + (yz-ys)²
1
Find the distance, d, of AB.
A = (2, -3) B = (4, 5)
Next, add the squares.
A
B
4
6
8
10
d = √(x₂-x₁)² + (Y2 − Y1)²
d = √(2)² + (8)²
d = √4 + 64
d = √ [?]
Submit

9 A 2 4 -2 4 2 (x2-x₁)² + (yz-ys)² 1 Find the distance, d, of AB. A = (2, -3) B = (4, 5) Next-example-1
User Cros
by
7.6k points

1 Answer

2 votes

The distance, d, of AB is 2√17

How to calculate distance between two coordinates points on a Cartesian coordinates.

A coordinate point refers to a specific location in a two-dimensional space, typically denoted as (x, y). The x value represents the horizontal position on the x-axis, and the (y) value represents the vertical position on the y-axis. These values specify the unique position of a point in a coordinate system.

Given points A(2,-3) and B(4,5)

The distance between the points is found by using the distance formula.

d = √(x₂-x₁)² + (y₂ − y₁)²

where

x₁ = 2, x₂ = 4

y₁ = -3, y₂ = 5

Substitute into d = √(x₂-x₁)² + (y₂ − y₁)²

d = √(4-2)² + (5− (-3))²

= √(2)² + (5 + 3)²

d = √(2)² + (8)²

d = √4 + 64

d = √ [68]

d = 2√17

Therefore, distance d of AB is 2√17

User Robert Lee
by
7.4k points