201k views
0 votes
What is the molarity of a solution prepared from 29.2 grams of kno₃ in 425 milliliters of solutions?

1 Answer

6 votes

Final answer:

To find the molarity of a solution made with 29.2 grams of KNO₃ in 425 milliliters, calculate the moles of KNO₃, convert milliliters to liters, and then divide moles by liters to get a molarity of 0.680 M.

Step-by-step explanation:

To calculate the molarity of a solution prepared from 29.2 grams of KNO₃ in 425 milliliters of solution, we need to follow these steps:

  • First, determine the molar mass of KNO₃.
  • Next, calculate the number of moles of KNO₃.
  • Then, convert the volume of the solution from milliliters to liters.
  • Finally, divide the number of moles of KNO₃ by the volume of the solution in liters to find the molarity.

Let's assume the molar mass of KNO₃ is approximately 101 g/mol (please verify this with a periodic table). Now, we use the formula:

Number of moles = Mass (g) / Molar mass (g/mol)

Molarity (M) = Number of moles / Volume (L)

Number of moles = 29.2 g / 101 g/mol = 0.289 moles

Since we have 425 mL, we convert it to liters: 425 mL * (1 L / 1000 mL) = 0.425 L

Now, we calculate the molarity: 0.289 moles / 0.425 L = 0.680 M.

The molarity of the solution is therefore 0.680 M.

User Joshua Flanagan
by
7.7k points