Question

F(x) = 2x² + 12x + 16
What is the average rate of change of f(x) on the interval [-3, -2].

Answer 1

`\begin{array}{llll} f(x)~from\\\\ x_1 ~~ to ~~ x_2 \end{array}~\hfill slope = m \implies \cfrac{ \stackrel{rise}{f(x_2) - f(x_1)}}{ \underset{run}{x_2 - x_1}}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array} \\\\[-0.35em] ~\dotfill`

`f(x)= 2x^2 + 12x +16 \qquad \begin{cases} x_1=-3\\ x_2=-2 \end{cases}\implies \cfrac{f(-2)-f(-3)}{-2 -( -3)} \\\\\\ \cfrac{[2(-2)^2 + 12(-2) + 16]~~ - ~~[2(-3)^2 + 12(-3) + 16]}{-2+3} \\\\\\ \cfrac{[8-24+16]~~ - ~~[18-36+16]}{1}\implies 0-(-2)\implies \text{\LARGE 2}`