Final answer:
A) To solve for Fn/Fa, we use the equation Fn/Fa = (1400 kg * 9.8 m/s²) / (0.9 * (1400 kg * 9.8 m/s²)), which simplifies to Fn/Fa = 1/0.9. This results in Fn/Fa being approximately 1.11. B) The frictional force to stop the car on a sunny day can be calculated using the equation Fa = 0.9 * (1400 kg * 9.8 m/s²), which gives a value of 12348 N.
Step-by-step explanation:
To solve for Fn/Fa, we first need to understand that Fn is the normal force and Fa is the frictional force. The normal force is equal to the weight of the car, which can be calculated as Fn = m * g, where m is the mass of the car and g is the acceleration due to gravity (9.8 m/s^2). So, Fn = 1400 kg * 9.8 m/s².
The frictional force can be calculated as Fa = coefficient of friction * Fn. Plugging in the given coefficient of friction (0.9) and the calculated value of Fn, we find Fa = 0.9 * (1400 kg * 9.8 m/s²).
A) In terms of the equation used, we have:
Fn/Fa = (1400 kg * 9.8 m/s²) / (0.9 * (1400 kg * 9.8 m/s²))
Fn/Fa = 1/0.9
Fn/Fa = 1.11
So, Fn/Fa is approximately 1.11.
B) To calculate the frictional force that would stop the car on a sunny day, we use the equation Fa = coefficient of friction * Fn.
Plugging in the given coefficient of friction (0.9) and the calculated value of Fn (1400 kg * 9.8 m/s²), we find Fa = 0.9 * (1400 kg * 9.8 m/s²).
In terms of the equation used, we have:
Fa = 0.9 * (1400 kg * 9.8 m/s²)
Fa = 0.9 * (13720 N)
Fa = 12348 N
So, the frictional force to stop the car on a sunny day would be 12348 N.