Final answer:
The maximum voltage that can be connected across a 12,000 Ω resistor rated at 2.5 watts is approximately 173.21 volts, calculated using the formula V = √(P × R).
Step-by-step explanation:
The question involves calculating the maximum voltage that can be applied to a 12,000 Ω resistor rated at 2.5 watts. To find this voltage, we can use the power formula related to resistance and voltage, which is:
P = V^2 / R
Where P represents power in watts, V represents voltage in volts, and R represents resistance in ohms. By rearranging this formula to solve for V, we obtain:
V = √(P × R)
Substituting the given values for power (P = 2.5 W) and resistance (R = 12,000 Ω) into this formula, we calculate the maximum voltage as follows:
V = √(2.5 W × 12,000 Ω)
V = √(30,000 WΩ)
V = 173.21 volts
Therefore, the maximum voltage that should be connected across a 12,000 Ω resistor rated at 2.5 watts is approximately 173.21 volts.