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Yellowstone National Park has an average of about 4500 bison living in it. The park covers 3472 square miles. What is the population density of bison living in Yellowstone?

a.
1.3 bison/mi2
b.
16 bison/mi2
c.
77 bison/mi2
d.
0.77 bison/mi2


Please select the best answer from the choices provided

A
B
C
D

1 Answer

0 votes

Final answer:

The population density of bison living in Yellowstone National Park is calculated by dividing the number of bison by the park's area, resulting in approximately 1.3 bison per square mile.

Step-by-step explanation:

The question asks for the population density of bison in Yellowstone National Park.

To find population density, you divide the population by the area it occupies.

In this case, divide 4500 bison by 3472 square miles.

Population density = Number of bison / Total area in square miles

Population density = 4500 / 3472

≈ 1.3 bison per square mile.

Therefore, the correct answer for the population density of bison living in Yellowstone is option a, which is 1.3 bison/mi2.