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Find the compenent form of the vector with the direction angle 287 and magnitude 11

User Bitprophet
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1 Answer

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Final answer:

The component form of the vector with a direction angle of 287 degrees and a magnitude of 11 is approximately (3.216, -10.5193), found using the cosine and sine of the angle for the x and y components respectively.

Step-by-step explanation:

To find the component form of a vector with a direction angle of 287 degrees and a magnitude of 11, use trigonometric functions based on the angle given. For the x-component (horizontal), use cosine, and for the y-component (vertical), use sine.

The expressions will look like this:
x-component = magnitude × cos(angle)

y-component = magnitude × sin(angle)

Since the angle is measured counter-clockwise from the positive x-axis, a 287-degree angle indicates the vector is in the fourth quadrant, where the x-component is positive and the y-component is negative.

Component form calculations:

x-component = 11 × cos(287°) = 11 × cos(-73°)

≈ 11 × 0.2924

≈ 3.216

y-component = 11 × sin(287°)

= 11 × sin(-73°)

≈ 11 × -0.9563

≈ -10.5193

Therefore, the component form of the vector is approximately (3.216, -10.5193).

User Verbeia
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