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I need help PLEASE !!!! Write a cosine function that has an amplitude of 2, a midline of 4 and a period of 4.

User Jits
by
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1 Answer

4 votes

Answer:


\mathbf{y = 2cos ( (\pi)/(2)(x - 0) + 4}

Explanation:

The standardized cosine function is ;


\mathbf{y = Acos (Bx + C) +D}

Amplitude |A| = 2

Period
(2 \pi)/(B )= 4

2π = 4B


B = (2 \pi)/(4)


B = (\pi)/(2)

Midline y = 4; D = 4

Phase shift; since no phase shift is given; then C = 0

The cosine function:
\mathbf{y = 2cos ( (\pi)/(2)(x - 0) + 4}

User DWolf
by
8.5k points

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