Question

Can someone show the working for this question ​

Answer 1

The sum of the oxidation states of Mn and N is smallest in Row A and Row D.

Let's do the calculation for each row.

Row A:
`MnCl_4` and
`N_2`

Oxidation state of Mn in
`MnCl_4` is +2.

Oxidation state of N in
`N_2` is 0.

Sum = +2 + 0 = +2

Row B:
`MnCO_3` and
`NO_2^-`

Oxidation state of Mn in
`MnCO_3` is +2.

Oxidation state of N in
`NO_2^-` is +4.

Sum = +2 + +4 = +6

Row C:
`K_2MnO_4` and NH4+

Oxidation state of Mn in
`K_2MnO_4` is +6.

Oxidation state of N in NH4+ is -3.

Sum = +6 + -3 = +3

Row D:
`Mn(OH)_3` and
`NH_2OH`

Oxidation state of Mn in
`Mn(OH)_3` is +3.

Oxidation state of N in
`NH_2OH` is -1.

Sum = +3 + -1 = +2

Therefore, the sum of the oxidation states of Mn and N is smallest in Row A and Row D.